The Below Rexx function STRREPLACE can replace a part of a string with a new one
/*REXX*/ MYSTR = 'MY TEST STRING' SAY MYSTR MYSTR = STRREPLACE(MYSTR,'TEST','NEW') SAY MYSTR EXIT /* A FUNCTION TO DO A STRING REPLACE */ STRREPLACE: ORIGINAL = ARG(1) OLDTXT = ARG(2) NEWTXT = ARG(3) /* YOU CAN CHANGE THE BELOW KEY (TMPTXT), WHICH IS USED AS A TEMPORARY POINTER TO IDENTIFY THE TEXT TO BE REPLACED */ TMPTXT = '6A53CD2EW1F' NEWSTR = ORIGINAL DO WHILE POS(OLDTXT,NEWSTR) > 0 NEWSTR = SUBSTR(NEWSTR, 1 , POS(OLDTXT,NEWSTR)-1) ||, TMPTXT || SUBSTR(NEWSTR, POS(OLDTXT,NEWSTR) + LENGTH(OLDTXT)) END DO WHILE POS(TMPTXT,NEWSTR) > 0 NEWSTR = SUBSTR(NEWSTR, 1 , POS(TMPTXT,NEWSTR)-1) ||, NEWTXT || SUBSTR(NEWSTR, POS(TMPTXT,NEWSTR) + LENGTH(TMPTXT)) END RETURN NEWSTR
Use this code 
Thank you for that.
At the 16th line, must be NEWTX and not NEW
Thanks PeUR, Corrected!
scenario:
str = ‘ my new ride ‘
old text = ‘new’
new text = ‘new first’
code will enter in an endless loop…
share yer thougts!
oh.. yes, if the old text is a sub string of new text, there will be an infinite loop.. I have now updated the code, such that it will work even for the case you mentioned
Thanks!
Appreciate your work!!!
Very nice. Big thanks. I used it to rplace all occurances I have in a string where there are two commas side by side with comma X comma. I could then do a WORDS to get a count of words in the string. That helped in putting all the words into a compound variable when the total of words are unpredictable.